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Alexxandr [17]
3 years ago
14

Find the equation of a line, in slope-intercept form, that is parallel to y = 3x + 5, and passes through (5, 11)

Mathematics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

y=3x-4

Step-by-step explanation:

You might be interested in
Researchers are investigating the effectiveness of leg-strength training on cycling performance. A sample of 7 men will be selec
ruslelena [56]

Answer:

A. The interval will be narrower if 15 men are used in the sample.

Step-by-step explanation:

Hello!

When all other things remain the same, which of the following statements about the width of the interval is correct?

A. The interval will be narrower if 15 men are used in the sample.

B. The interval will be wider if 15 men are used in the sample.

C. The interval will be narrower if 5 men are used in the sample.

D. The interval will be narrower if the level is increased to 99% confidence.

E. The interval will be wider if the level is decreased to 90% confidence.

Consider that the variable of interest "Xd: Difference between the peak power of a cyclist before training and after training" has a normal distribution. To construct the confidence interval for the population mean of the difference you have to use a pooled t-test.

The general structure for the CI is "point estimate"±" margin fo error"

Any modification to the sample size, sample variance and/or the confidence level affect the length of the interval (amplitude) and the margin of error (semiamplitude)

The margin of error of the interval is:

d= t_{n-1;1-\alpha /2} * (Sd/n)

1) The sample size changes, all other terms of the interval stay the same.

As you can see the margin of error and the sample size (n) have an indirect relationship. This means, that when the sample size increases, the semiamplitude decreases, and when the sample size decreases, the semiamplitude increases.

↓d= t_{n-1;1-\alpha /2} * (Sd/↑n)

↑d= t_{n-1;1-\alpha /2} * (Sd/↓n)

Correct option: A. The interval will be narrower if 15 men are used in the sample.

2) The confidence level has a direct relationship with the semiamplitude of the interval, this means that when the confidence level increases, so do the semiamplitude, and if the level decreases, so do the semiamplitude:

↓d= ↓t_{n-1;1-\alpha /2} * (Sd/n)

↑d= ↑t_{n-1;1-\alpha /2} * (Sd/n)

I hope it helps!

4 0
4 years ago
Quick algebra 1 question for 10 points!
zaharov [31]

<u>Answer:</u>

○ x = -7

<u>Step-by-step explanation:</u>

Given the equation:

10(x + 10) - 4 = 11 - 5(2x + 11),

to solve for x, we have to rearrange the equation to make x its subject.

10(x + 10) - 4 = 11 - 5(2x + 11)

⇒ 10x + 100 - 4 = 11 - 10x -55      [expand brackets]

⇒ 10x + 96 = -44 - 10x

⇒ 10x + 10x + 96 = -44                   [add 10x to both sides]

⇒ 20x + 96 = -44

⇒ 20x = -44 - 96                             [subtract 96 from both sides]

⇒ 20x = -140

⇒ x = \frac{-140}{20}                                        [divide both sides by 20]

⇒ x = \bf-7

6 0
2 years ago
Read 2 more answers
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
Giovanni justifies whether the expression -4x-8 is equivalent to -2(x+1)-2(x+3) by letting x=3 in both expressions. What is the
Lorico [155]

Answer:

The value of each expression when x=3 will be -20 and -20.

Step-by-step explanation:

Given the expression

-4x-8

setting x=3

= -4(3)-8

=-12-8

=-20

Given the expression

-2(x+1)-2(x+3)

setting x=3

=-2(3+1)-2(3+3)

=-2(4)-2(6)

=-8-12

=-20

so we conclude that the value of both the expressions was -20 when we substituted the value x=3.

Therefore, the value of each expression when x=3 will be -20 and -20.

3 0
3 years ago
7+9+(12—8)\2x4 HELP ME PLEASE!!
Talja [164]

Answer:

i think it is The result can be shown in multiple forms.

Exact Form:

83\8

Decimal Form:

10.375

Mixed Number Form:

10 3\8

Step-by-step explanation:

i might be wrong and if i am im sorr ._.

4 0
3 years ago
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