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umka2103 [35]
3 years ago
12

In preparation for wedding egg and bought 60 candles. He paid $0.37 for each candle his sister bought 170 candles at the same pr

ice how much more money in dollars did Aidan sister spend?
Mathematics
1 answer:
pshichka [43]3 years ago
5 0
She spent:

170 * 0.37 = $62.90

He spent:

60 * 0.37 = $22.20

So the difference is:

62.90 - 22.20 = <u>$40.70</u>
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Which of the following numbers is between 0.40 and 0.47 ?
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The Answer is 21/50 which is = 0.42

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1. A triangle is rotated 35° about the origin. What is true about the relationship be pre-image?
jasenka [17]

Answer:

the triangles are equivalent

Step-by-step explanation:

that's it

5 0
2 years ago
CAN SOMEONE HELP ME !!!!!!!!!
MissTica

Answer:

She will get <u>80mg</u> of dextromethorphan and <u>800mg</u> of guaifenesin. And the bottle last for <u>6 days</u> approximately.

Step-by-step explanation:

Given that the Robitussin DM contains dextromethorphan 10mg/5mL and gualfenesin 100mg/5mL. And we are also given that Mrs Smith took four doses and each dose is 2 teaspoons=2X5=10mL.

So, four doses=4X10=40mL.

So, dextromethorphan in 4 doses is = \frac{10}{5}X40=80mg

And Guaifenesin in 4 doses is = \frac{100}{5}X40=800mg

Dosage of medicine daily she has to take=40mL and the bottle contains 237 mL. Hence the number of days bottle last = \frac{237}{40}=5.925≈6 days approximately.

7 0
2 years ago
One set of markers cost x dollars. How much would set of makers and crayons cost together
inysia [295]

Answer:

x+y

Step-by-step explanation:

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Hope this helps! Have a nice day <3

3 0
2 years ago
Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R
Anni [7]

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

6 0
2 years ago
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