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aalyn [17]
3 years ago
7

Jennifer is saving money to buy a bike. The bike costs $258. She has $125 saved, and each week she adds $19 to her savings.

Mathematics
2 answers:
makvit [3.9K]3 years ago
6 0

Answer:

7 weeks

Step-by-step explanation:

nadya68 [22]3 years ago
6 0

Answer:

7 weeks

Step-by-step explanation:

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Select the postulate that is illustrated for the real numbers. 2(x + 3) = 2x + 6 The commutative postulate for multiplication Mu
madam [21]

Answer:


Step-by-step explanation:

Postulate 5: If two planes intersect, then their intersection is a line.

4 0
3 years ago
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Which number line represents the solutions to |–2x| = 4?
GenaCL600 [577]
The third one is the correct choice because the solutions are 2 and -2
7 0
3 years ago
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25÷2 3/8 I need the anser please​
lora16 [44]

Answer:- 100/3 in fraction or you can write I decimal too (33.33)

7 0
3 years ago
Suppose that a box contains one fair coin (Heads and Tails are equally likely) and one coin with Heads on each side. Suppose fur
stealth61 [152]

Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Three heads.
  • Event B: Fair coin.

The probability associated with 3 heads are:

  • 0.5^3 = 0.125 out of 0.5(fair coin).
  • 1 out of 0.5(biased).

Hence:

P(A) = 0.125 + 0.5 = 0.625

The probability of 3 heads and the fair coin is:

P(A \cap B) = 0.5(0.125) = 0.0625

Then, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0625}{0.625} = 0.1

0.1 = 10% probability that the chosen coin was the fair coin.

A similar problem is given at brainly.com/question/14398287

4 0
3 years ago
Line DB bisects ∠ABC, m∠ABD = 4x, and m∠DBC = x + 36. Find m∠ABC. Choose True or False for each statement.
lapo4ka [179]

Since DB bisects ∠ABC and ∠ABC= ∠ABD + ∠DBC, then

∠ABD = ∠DBC, that is

4x = x + 36 ( subtract x from both sides )

3x = 36 ( divide both sides by 3 )

x = 12

∠ABD = 4x = 4× 12 = 48°

∠DBC= x + 36 = 12 + 36 = 48°

∠ABC = 48° + 48° = 96°

Thus statement A is FALSE

statement B is TRUE

statement C is TRUE


4 0
4 years ago
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