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horsena [70]
3 years ago
6

Freee brainliest for iconic

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer:

hi lol I need to type 20 characters

Vikki [24]3 years ago
7 0

Answer:

Thx vro. If you need a iconic go to jaden smith he's icon living

Step-by-step explanation:

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Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the
nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

A = 6 * 81

A = 486 inches^2

3 0
3 years ago
-4/5(-8x+6)=1+7 Please Help
bagirrra123 [75]

Answer:

x = 2

Step-by-step explanation:

-4/5(-8x + 6) = 1 + 7 (distribute first)

6.4x -4.8 = 8 (add 4.8 on both sides)

6.4x = 12.8 (divide by 6.4)

x = 2

PLUG IN

-4/5(-8(2) + 6) = 1 + 7

-4/5(-16 + 6) = 8

-4/5(-10) = 8

8 = 8

8 0
3 years ago
Can someone help with this math question
Tcecarenko [31]
Based on corresponding angles, the upper left angle will be the supplement of 130, which is 50 degrees. The upper right angle is perpendicular, so it is 90 degrees. Since the sum of all internal angles of a triangle is 180, the remaining angle (lower angle) is 40 degrees. This is choice G.
6 0
3 years ago
How to solve 4y=x 3x- y=70 using substitution
creativ13 [48]
X = 4y
3x - y = 70

substitute the x in the second equation with the other half of the first equation.

3(4y) - y = 70
12y - y = 70
11y = 70
y = 6.36 repeating, or 6 4/11

now use this to solve first equation
x = 4 (6 4/11)
x = 25.45 repeating

done
7 0
3 years ago
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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