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Ksenya-84 [330]

2 years ago

14

To check the condition that the sample size is large enough before applying the Central Limit Theorem for Sample Proportions, r

esearchers can verify that the products of the sample size times the sample proportion and the sample size times are both greater than or equal to what number?
a.100
b.50
c.5
d.10

1 answer:

skad [1K]2 years ago

4 0

Answer:

a. 1o0

Step-by-step explanation:

You might be interested in

Write the equation of a line that meets all the following requirements:

LuckyWell [14K]

9514 1404 393

Answer:

x + y = 5
y = -x + 5

Step-by-step explanation:

We can start with the point-slope form of the equation for a line. To meet the given requirements, we can use a point of (5, 0) and a slope of -1. Then the equation in that form is ...

y -0 = -1(x -5)

Simplifying gives the slope-intercept form:

y = -x +5 . . . . . . . use the distributive property to eliminate parentheses

Adding x to both sides gives the standard form:

x + y = 5

__

<em>Explanation</em>

We know the line has the required intercept and slope because we chose those values to put into the point-slope form. Conversion from one form to another made use of the rules of equality, the additive identity element (y-0=y), and the distributive property.

8 0

2 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

What does x is greater than 5 mean

kotegsom [21]

Answer:

That x is any number bigger that 5 so 6 plus

Step-by-step explanation:

3 0

3 years ago

If you have a decimal answer, round to the nearest tenth!<br> x/-4−3=0

lions [1.4K]

X = -12 !!

so first rewrite the fraction
multiply both sides
move the constant to the right
change the signs
then you have your solution

5 0

2 years ago

PLZ HELP I WILL MARK AS BRAINLIEST

-Dominant- [34]

Answer:

7 square units

Step-by-step explanation:

As with many geometry problems, there are several ways you can work this.

Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.

The applicable formulas are ...

area of a trapezoid: A = (1/2)(b1 +b2)h

area of a triangle: A = (1/2)bh

So, our areas are ...

AQRS = AWSQE - AWSR - AEQR

= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)

Factoring out 1/2, we have ...

= (1/2)((2+5)·4 -2·2 -5·2)

= (1/2)(28 -4 -10) = 7 . . . . square units

4 0

2 years ago