Can't answer.
Needs number of rentals from that day.
35 square units is the answer
Answer:
x=3
Step-by-step explanation:
Simplifying
2(6x + 9 + -3x) = 5x + 21
Reorder the terms:
2(9 + 6x + -3x) = 5x + 21
Combine like terms: 6x + -3x = 3x
2(9 + 3x) = 5x + 21
(9 * 2 + 3x * 2) = 5x + 21
(18 + 6x) = 5x + 21
Reorder the terms:
18 + 6x = 21 + 5x
Solving
18 + 6x = 21 + 5x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-5x' to each side of the equation.
18 + 6x + -5x = 21 + 5x + -5x
Combine like terms: 6x + -5x = 1x
18 + 1x = 21 + 5x + -5x
Combine like terms: 5x + -5x = 0
18 + 1x = 21 + 0
18 + 1x = 21
Add '-18' to each side of the equation.
18 + -18 + 1x = 21 + -18
Combine like terms: 18 + -18 = 0
0 + 1x = 21 + -18
1x = 21 + -18
Combine like terms: 21 + -18 = 3
1x = 3
Divide each side by '1'.
x = 3
P ( A and B ) = 0.051.
P ( B ) = 0.32
According to Bayes` rule:
P ( A\B ) = P ( A and B ) /P ( B ) = 0.051/ 0.32 = 0.159375 ≈ 0.159
Answer: B ) 0.159
Answer:
Yes, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
Step-by-step explanation:
H0 : σ² = 2.66²
H1 : σ² < 2.66²
X²c = (n - 1)*s² ÷ σ²
sample size, n = 40
Sample standard deviation, s = 1.9
X²c = ((40 - 1) * 1.9²) ÷ 2.66²
X²c = 140.79 ÷ 7.0756
X²c = 19.897
Using a confidence level of 95%
Degree of freedom, df = n - 1 ; df = 40 - 1 = 39
The critical value using the chi distribution table is 25.6954
Comparing the test statistic with the critical value :
19.897 < 25.6954
Test statistic < Critical value ; Reject the Null
Hence, we can conclude that the population standard deviation of TV watching times for teenagers is less than 2.66
