Determine the number of solutions of the system. y = 2x - 1 y = -2x + 3

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

The answer to this is the system has no solution.

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Last month, Lana sold 35 necklaces a week at $15 each. However, throughout the month, 6 customers returned their necklaces for a

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35 necklaces multiplied by 4 weeks is 140. Multiply 140 by 15, representing the amount of money each necklace costs and you get 2,100. That is the total amount sold, but because the 6 costumers brought their necklaces back, you have to take 6 times 15 to see how much the total returned necklaces cost. That would be $210, so you take $2,100 and subtract $210, and your answer is $1,180. That is the final answer.

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Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

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In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,