Answer:
Part A)
This quadratic expression can be factored by using the difference of squares pattern.
Part B) (5x+y) and (5x-y)
Step-by-step explanation:
Given:
25x^2-y^2
above polynomial can be factorize by using difference of squares formula
a2-b2=(a+b)(a-b)
25x^2-y^2= (5x-y)(5x+y)
so for part A)
correct option is This quadratic expression can be factored by using the difference of squares pattern.
Part B)
As factored above in part A,
the factors of given polynomial 25x^2-y^2 are (5x+y)(5x-y)
so for part B) correct options are (5x+y) and (5x-y) !
Answer:
-23.21
Step-by-step explanation:
Edge 2021
54 5 270
------- × ------- = --------- = 45
1 6 6
28 2 56
------- × ------ = ------- = 8
1 7 7
just multiply 8 until you make it to 200 or the closest around 200
8 x 25 = 200
Given:
To find:
The value of 
.
Solution:
We have,
Using properties of log, we get
![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute and .
Therefore, the value of is 
.
