Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Answer:
79
Step-by-step explanation:
(58+88+80+70+ x)/5=75
75*5=296x
375=296x
x=375-296
x=79
Answer:
Ed and Sheerie save 7.5%.
Step-by-step explanation:
This question can be solved using a rule of three.
Ed and Sherrie save $90 each pay period from their combined paychecks, which total $1200. What percent do Ed and Sherrie save?
How much of $1200 is $90? $1200 is 100% = 1, $90 = x. So
$1200 - 1
$90 - x
Ed and Sheerie save 7.5%.
A: 45x + 30y = 1350
Since we don’t know how many adults and children are in the group, we use x and y
b: x-intercept= 30 y-intercept=45
To find the x-intercept you need to isolate the variable. 45x/45 = x
Then you do the same thing to the other side. 1350/45 = 30
So x=30
Same thing with the y-intercept.
30y/30 = y 1350/30 = 45
y=45 (Not really sure what it means by “what they represent” but I thinks it’s that there are 30 adult tickets and 45 children tickets )
c: so our points are (30,0) and (0,45) so you would graph that.
To find how many children tickets were bought if there were 20 adult tickets just look at the photo I put. I don’t know how to explain this.
Hope this helps
The solutions to q² - 125 = 0 are q = ±√125.
q = -5√5
q = 5√5