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3 years ago

An algebraic expression for 19 less than a number times 7.

Mathematics

1 answer:

raketka [301]3 years ago

6 0

Answer:

I have zero idea what you mean im sorry this is a bad answer

Step-by-step explanation:

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Un motor de combustión interna que cumple el ciclo ideal de Otto, funciona con aire como gas ideal. Tras el proceso de admisión

sineoko [7]

Answer:

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Step-by-step explanation:

6 0

3 years ago

T(x)=2x-9/x-a t(1)=1 Value of a?

Misha Larkins [42]

t(1) = 1 = 2(1)-9 / 1 - a

1 - a = 2 - 9 = -7

a = 1 + 7

a = 8 answer

4 0

3 years ago

Courtlynn combines 7/8 cup sour cream with 1/2 cream cheese she then divides the mixture between 2 bowls how much mixture does c

natta225 [31]

7/8 + 4/8= 11/8 so 11/8 ÷2 = 5.5/8 she puts 5 1/2 /8 cups of the mixture in each bowl

4 0

4 years ago

Read 2 more answers

6(x+7)+4=-8(x-5)-2 solve for x

NikAS [45]

Answer:

x=-4/7

Step-by-step explanation:

We are given an equation as

6(x+7)+4=-8(x-5)-2

and asked to solve for x

Simplify to get

Distribute 6 over x+7 and on right side -8 over x-5

6x+42+4 = -8x+40-2

Take -8x to left side to become +8x and 46 to right side to become -46

Grouping like terms

14x = 38-46 = -8

Divide by 14

x = -8/14 = -4/7

Since this is an equation, we get a single value for x

and answer is -4/7

4 0

3 years ago

Over the past several years, the owner of a boutique on Aspen Avenue has observed a pattern in the amount of revenue for the sto

Sidana [21]

Answer:

$f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500$

Step-by-step explanation:

Given information:

Maximum revenue = 42000

Minimum revenue = $25000

Time period = 12 months

We need to write a function that models the boutique's revenue during the year, where corresponds to the month.

$f(x)=Asin(B[x-C])+D$ .... (1)

where, A is amplitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is midline.

$A=Amplitude =\frac{Maximum-Minimum}{2}\Rightarrow \frac{42000-25000}{2}=8500$

$D=midline =\frac{Maximum+Minimum}{2}\Rightarrow \frac{42000+25000}{2}=33500$

$Period=\frac{2\pi}{B}$

$12=\frac{2\pi}{B}\Rightarrow B=\frac{\pi}{6}$

Substitute the value of A, B and D in equation (1).

$f(x)=8500\sin\left(\frac{\pi}{6}\left(x-C\right)\right)+33500$ ..... (2)

In April, revenue of the store is $42000. So, the graph passes through the point (4,42000).

$42000=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)+33500$

$42000-33500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

$8500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

Divide both sides by 8500.

$1=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

$\sin \frac{\pi}{2}=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

On comparing both sides we get

$\frac{\pi}{2}=\frac{\pi}{6}(4-C)$

$3=4-C$

$C=4-3$

$C=1$

Substitute the value of C in equation (2).

Therefore, the required function is $f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500$ .

5 0

3 years ago