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Triss [41]
3 years ago
13

What is cos X? picture provided below

Mathematics
2 answers:
olasank [31]3 years ago
5 0


SOH-CAH-TOA
Sine = Opposite over Hypotenuse,  Cosine = Adjacent over Hypotenuse and Tangent = Opposite over Adjacent 

Hey Dewild,

Remember this for cosign or cos. COS = Adjacent over Hypotenuse

24/26 = 0.92
Fiesta28 [93]3 years ago
3 0
Hypotenuse is zx
and adjacent is yz then cos x=10/24
You might be interested in
Can anyone please help me :)
Solnce55 [7]

Answer:

5 to the 15th power.

Step-by-step explanation:

PEMDAS requires us to do parenthesis, then exponents, and then division. Let's do 5³. 5x5x5 is equal to 125. Now, we find 125 to the ninth power. According to my calculations, 125 to the ninth power is equal to 7,450,580,596,923,828,125. Now, we find 5 to the twelfth power, which, according to my calculations, is 244,140,625. Now, we solve. According to my calculations, 7,450,580,596,923,828,125/244,140,625 is equal to 30,517,578,125. 30,517,578,125 is equivalent to 5 to the 15th power. That means that the second option is correct. I hope this helps!

3 0
3 years ago
What’s the volume of one cylinder?
r-ruslan [8.4K]

Answer:

For the first one its: Volume = 402.12in³

For the second one its: Volume = 201.0619 in³

Step-by-step explanation:

For the first one work:

Volume = 3.1416 x 42 x 8

= 3.1416 x 16 x 8

For the second one work:

Volume = 3.1416 x 42 x 4

= 3.1416 x 16 x 4

5 0
3 years ago
Read 2 more answers
In each reaction box, place the best reagent and conditions from the list below.
zloy xaker [14]
I thin the best answer among the following choices base on the data you have given and the formulas, to be honest I didn't really understand the instructions but in your diagram, this is just my suggestion but no an answer, the value of #1 2nd option from the left of the first line and the #2 is the last choice from the first line.  I hope this would help
3 0
4 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
4 years ago
Is one over eight irrational or rational
lukranit [14]
The answer to this is irrational
4 0
3 years ago
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