There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.
Even means the graph is symmetric about the y-axis
The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)
because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).
Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
Answer:
138 is the answer
Step-by-step explanation:
128 square
7+5=12 so it can be one of these 8+4=12, 9+3=12, 10+2=12, and 11+1=12.
Answer:
a) The equation of the Parallel line to the given straight line is
6 x + y + 13 =0
b) Slope - intercept form
y = - 6 x - 13
c) The intercept - form

x - intercept = 
y - intercept = - 13
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given the equation of the straight line
y = -6x +1
6 x + y - 1 = 0
The equation of the Parallel line to the given straight line is
6x + y + k=0 and it passes through the point (-3, 5 )
⇒ 6 (-3 ) + 5 + k =0
⇒ - 18 + 5 + k=0
⇒ -13 + k = 0
⇒ k = 13
The equation of the Parallel line to the given straight line is
6 x + y + 13 =0
<u><em>Step(ii):-</em></u>
Slope - intercept form
y = m x + C
y = - 6 x - 13
<u><em>Step(iii)</em></u>:-
Intercept - form
6 x + y + 13 =0
6 x + y = - 13


The intercept - form

x - intercept = 
y - intercept = - 13