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nikitadnepr [17]
3 years ago
5

Write an equation of the line that passes through a pair of points:

Mathematics
2 answers:
Shalnov [3]3 years ago
4 0

Answer:

Step-by-step explanation:

(-2,-2) , (5,-5)

Slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{-5-(-2)}{5-(-2)}\\\\=\frac{-5+2}{5+2}\\\\=\frac{-3}{7}\\

(-2,-2), m= -3/7

Line equation: y -y1 =m*(x -x1)

y-(-2) = -(-3/7)(x - [-2])

y+2=\frac{-3}{7}*(x+2)\\\\y+2=\frac{-3}{7}*x+(\frac{-3}{7})*2\\\\y+2=\frac{-3}{7}x-\frac{6}{7}\\\\y=\frac{-3}{7}x-\frac{6}{7}-2\\\\y=\frac{-3}{7}x-\frac{6}{7}-\frac{2*7}{1*7}\\\\y=\frac{-3}{7}x-\frac{6}{7}-\frac{14}{7}\\\\y=\frac{-3}{7}x-\frac{20}{7}

Rom4ik [11]3 years ago
4 0

Answer:

y = -(3/7)x - 20/7

Step-by-step explanation:

Slope: (-5 - -2)/(5 - -2)

= -3/7

y = (-3/7)x + c

-2 = (-3/7)(-2) + c

-2 - 6/7 = c

c = -20/7

y = -(3/7)x - 20/7

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