Answer:
Claim is false
Step-by-step explanation:
Claim : A credit reporting agency claims that the mean credit card debt in a town is greater than $3500.
n = 20
Since n <30
So we will use t test
Formula : 
s = standard deviation = 391
x = 3600
n = 20
Degree of freedom = n-1 = 20-1 = 19
α=0.10
So, using t table
= 1.72
t critical > t calculated
So we accept the null hypothesis
Hence we reject the claim that the mean credit card debt in a town is greater than $3500.
Step-by-step explanation:
Discount amount = discount%of marked price
= 20% of 250
= 20/100x250
=Rs 50
Answer:
0 ≤ an ≤ bn
The series ∑₁°° bn converges
The series ∑₁°° an converges by comparison to ∑₁°° bn.
0 ≤ an ≤ bn
The series ∑₁°° bn diverges
The comparison test is inconclusive for our choice of bn.
Step-by-step explanation:
an = 1 / (n² + n + 3) and bn = 1 / n²
The numerators are the same, and the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p > 1, so it converges.
Since the larger function converges, the smaller function also converges.
an = (3n − 1) / (6n² + 2n + 1) and bn = 1 / (2n)
If we rewrite bn as bn = (3n − 1) / (6n² − 2n), we can tell that when the numerators are equal, the denominator of an is greater than the denominator of bn. So 0 ≤ an ≤ bn.
bn is a p series with p = 1, so it diverges.
The larger function diverges. We cannot conclude whether the smaller function converges or diverges.
Maybe for number of dots it can count by 5? (1,5) (2,10) (3,15) etc.
