Answer: B I think I hope it helps
Step-by-step explanation:
<em><u>Question:</u></em>
Ana participated in a charity walk. She raised $0.25 for each 1/2 mile that she walked.The first day Ana walked 11 miles.The second day, she walked 14 miles.How much money did Ana raised?
<em><u>Answer:</u></em>
Ana raised $ 12.5
<em><u>Solution:</u></em>
From given question,
First day walk = 11 miles
Second day walk = 14 miles
<em><u>Let us first calculate the total distance she walked</u></em>
Total distance = first day walk + second day walk
Total distance = 11 + 14 = 25 miles
Thus she walked for 25 miles
Given that,
<em><u>She raised $0.25 for each 1/2 mile that she walked</u></em>
Therefore, for 1 mile we get,
Now calculate for 25 miles
Thus she raised $ 12.5
We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3
the solutions are
x=√2+3
x=-√2+3
The answer is: The second one. Why?
Because, when it's a linear graph, the slope of the graph cannot change.
And that's the only graph that fits the criteria
Hope this helped! c:
Answer:
x<5
Step-by-step explanation:
the greater sign will firstly be changed to = for better solving so we obtain
3+9x=4(x+7)by opening bracket
3+9x=4x+28
9x-4x=28-3
5x=25
divide all through by 5x
we obtain
x=5
the greater sign change here
which is x<5