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zubka84 [21]
3 years ago
6

Write the equation x2+24x+60=0 in the form (x+p)2=q

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

(x+12)^2=84

Step-by-step explanation:

x^2+24x+60=0

x^2+24x=-60

x^2+24x+(24/2)^2=-60+(24/2)^2

(x+24/2)^2=84

(x+12)^2=84 (ans)

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Robert and Chris can skate 4 miles in 18 minutes. How far can they ride in 45 minutes?​
adell [148]

Answer: Robert and Chris can skate 10 miles in 45 minutes.

Step-by-step explanation:

Let's start by finding the unit rate.

\frac{4}{18} =\frac{2}{9} \\\frac{18}{18} =1

Robert and Chris can skate \frac{2}{9} of a mile in 1 minute. Now we can multiply both by 45 to see how far the can go in 45 minutes.

(\frac{2}{9}) (\frac{45}{1} )\\\frac{(2)(45)}{(9)(1)} \\\frac{90}{9} \\10

45x1=45

The can skate 10 miles in 45 minutes.

6 0
3 years ago
115. Sami opens an account and deposits $100 into it at the end of each month. The account earns 2% per year compounded monthly.
givi [52]

Step-by-step explanation:

Geometric series.

Month 3.

      100(1+\frac{0.02}{12})^2 + 100(1+\frac{0.02}{12})+100

Month 4.

100( 1 + \frac{0.02}{12})^3 + 100( 1 + \frac{0.02}{12})^2+100(1+\frac{0.02}{12})+100

Month 5.

100(1 + \frac{0.02}{12})^4 + 100(1 + \frac{0.02}{12})^3 + 100(1 + \frac{0.02}{12})^2 +100( 1 + \frac{0.02}{12}) + 100

4 0
3 years ago
How long will it take a $2 000 investment to earn $544 in interest at a 1.7 interest rate
lozanna [386]

Answer:

16 years

Step-by-step explanation:

1.7% of 2000 is $34

$544 divided by $34 = 16 years, that is if the interest is yearly and not monthly though

7 0
3 years ago
How many terms are in the polynomial abcd + e-n2?<br>two<br>three<br>five<br>six​
ELEN [110]

Answer: There are 3 terms

Step-by-step explanation: You count the abcd as 1 term because it is all multiplied together, the e term is counted as another term, so there are 2 terms, and the n2 term is counted as a term getting you 3 terms in total.

3 0
3 years ago
What is the value of x
Zolol [24]

Answer:

765854sdfgh

Step-by-step explanation:

6 0
3 years ago
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