Answer:
Explanation:
def cvtToSeconds(hours,minutes,seconds):
total_seconds=3600*hours+60*minutes+seconds;
return total_seconds
def readData():
hours = eval(input("Enter Hours: "))
minutes = eval(input("Enter Minutes: "))
seconds = eval(input("Enter Seconds: "))
total_seconds=cvtToSeconds(hours,minutes,seconds)
print("Total Seconds: "+str(total_seconds))
readData()
The only one that would make sense in for this is C
Answer- C
Answer:
If one bulb goes out, the other bulbs will go out.
They are complicated to design and build.
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
V = i.r
120v = 5A x r
Resistance = 120:5 = 24 ohm
