Bye guys imma k.ill myself for real this time.

Which TranscribeMe tag should you use if you are unable to make out a word or phrase due to a difficult accent, poor audio, or a

Lady bird [3.3K]

Answer:

[inaudible]

Explanation:

TranscribeMe is an online transcription company. It employs people all over the world to render transcription services to clients. They have a style guideline which must be strictly adhered to by the transcribers. The guidelines specifically states the "do's " and "dont's" during transcription. Now, when transcribing a word or phrase that cannot be heard or understood due to poor audio or difficult answer, the transcriber uses the tag [inaudible].

5 0

3 years ago

What happens when a user clicks Accept on a meeting request?

melomori [17]

Explanation:

Other events at that time are canceled, and the meeting cannot be canceled by the organizer.

The agenda is updated with the user’s contact information, and other events at that time are canceled.

The meeting cannot be canceled by the organizer, and the agenda is updated with the user’s contact information.

The meeting organizer is notified, and a copy of the meeting is added to the user’s Outlook calendar.

3 0

3 years ago

Read 2 more answers

What is the inverse function of d(x ) = -2x - 6?

PtichkaEL [24]

Answer:

$-\frac{x}{2} - 3$

Explanation:

d(x) = -2x - 6

to find the inverse of a function, you need to follow these steps:

1. set d(x) = y

2. interchange the variables, so y becomes x and x becomes y

3. solve the equation for y

step 1: set d(x) = y

y = -2x -6

step 2: interchanging the variables

y = -2x - 6 turns into x = -2y - 6

step 3: solving for y

x = -2y - 6 < add 6 to both sides to get rid of it on the right

x + 6 = -2y < divide both sides by -2 to get y alone

x + 6 / -2 = $-\frac{x}{2} - 3$

-2y / -2 = y

$-\frac{x}{2} - 3$ = y

so the inverse of the function is $-\frac{x}{2} - 3$

7 0

3 years ago

In a "block" containment strategy, in which the attacker's path into the environment is disrupted, you should use the most preci

Slav-nsk [51]

The containment strategy prevents intruders from removing information assets from the network, and prevents attackers from using the organization's network as a launch point for subsequent attacks.
In a "block" containment strategy, in which the attacker's path into the environment is disrupted, you should use the most precise strategy possible, starting with blocking a specific IP address. Correct answer: C

8 0

3 years ago

Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3

Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0

3 years ago