Answer:
C, 3 1/2, 3 19/20, 3 39/40
Step-by-step explanation:
to make this a bit easier, we can put the mixed numbers into improper fractions:
3 39/40 becomes 159/40
3 19/20 becomes 79/20
3 1/2 becomes 7/2
comparing them to each other, we see they have unlike denominators. we need to get the denominators alike so we can compare them easier
the fractions all have a common denominator of 40, so we need to multiply each fraction by a number that gives us a denominator of 40
159/40 is already fine
79/20 needs to be multiplied by 2 to get a denominator of 40
79/20 x 2 = 158/40
7/2 needs to be multiplied by 20 to get a denominator of 40
7/2 x 20 = 140/40
from least to greatest, we have the following:
140/40, 158/40, 159/40
in their original form this would be:
3 1/2, 3 19/20, 3 39/40
the answer would be C
The answer is 20 I think so
18sqrt(x)
I'm assuming that 3(sqrt(x))5 is equal to 15sqrt(x). If that is the case, just perform the multiplication within each term and treat the sqrt(x) as a variable when you add the all together. It is okay because they are like terms.
How much does Taylor has?
