Question

Ill give all my points to someone who can solve this probability problem correctly and clearly to understand.

Answer 1

Answer:

+5.20 µC

Explanation:

Given that

Charge =−5.20 µC and radius= 5.40 cm.

Insert a +10.4- µC charge at the center of the sphere

As we know that according to  Gauss's theorem electric field inside the metal is zero.

When +10.4 µC charge insert but the total charge on the sphere should be  −5.20 µC.So the charge on the outer surface of the sphere will be +5.20 µC.