Answer: CasioFX-CG50
Step-by-step explanation: you can get it on amazon
Answer:
1,253 inches cubed
Step-by-step explanation:
This is easy, just find the separate volumes of both and add.
Figure 1: 7x5x5= 175 inches cubed
Figure 2: 11x14x7= 1,078 inches cubed
Added together: 1,253 inches cubed
Therefore it's C
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Answer:
d) f(x) = 5x + 2
Step-by-step explanation:
First we need to identify the variables and how they fit into the equation. in this case we know that the equation is f(x) = mx + b where f(x) is the total cost, m is the hourly cost, x is the number of hours bowled, and b is the price of the shoes.
Now, we need to solve for the hourly cost, so to do this we plug in all the known information to get 12 = m(2) + 2
To solve we need to isolate the variable by first subtracting 2 on both sides to get 10 = m(2) and then dividing both sides by 2 to get 5 = m.
Finally, since we now know that the hourly cost is $5 we can plug this information back into the equation to get f(x) = 5x + 2
Is that a snake in the pic
Answer:
- 891 = 3^4 · 11
- 23 = 23
- 504 = 2^3 · 3^2 · 7
- 230 = 2 · 5 · 23
Step-by-step explanation:
23 is a prime number. That fact informs the factorization of 23 and 230.
The sums of digits of the other two numbers are multiples of 9, so each is divisible by 9 = 3^2. Dividing 9 from each number puts the result in the range where your familiarity with multiplication tables comes into play.
891 = 9 · 99 = 9 · 9 · 11 = 3^4 · 11
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504 = 9 · 56 = 9 · 8 · 7 = 2^3 · 3^2 · 7
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230 = 10 · 23 = 2 · 5 · 23
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<em>Comment on divisibility rules</em>
Perhaps the easiest divisibility rule to remember is that a number is divisible by 9 if the sum of its digits is divisible by 9. That is also true for 3: if the sum of digits is divisible by 3, the number is divisible by 3. Another divisibility rule fall out from these: if an even number is divisible by 3, it is also divisible by 6. Of course any number ending in 0 or 5 is divisible by 5, and any number ending in 0 is divisible by 10.
Since 2, 3, and 5 are the first three primes, these rules can go a ways toward prime factorization if any of these primes are factors. That is, it can be helpful to remember these divisibility rules.
