3 years ago

Evaluate 3x^2 – 2xy - 4y^2

1 answer:

3 0

Evaluate for x=2,y=−3

3(22)−(2)(2)(−3)−4(−3)2

= C. −12

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Lelechka [254]

Answer:

-126

Step-by-step explanation:

For the binomial expression $(a-b)^{n}$ the coefficient of $(r+1)^{th}$ term is given by ${n \choose r} \times -1^{(r)}$ .

We have to find the coefficient of 6th term in the binomial expansion of

$(x^{3}-y^{4})^{9}$ .

Hence n=9 and r=5

The coefficient of 6th term = ${9 \choose 5} \times (-1)^{5}$

= $-{9 \choose 5}$

= -126

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