All categories

3 years ago

Need some help with this please

Mathematics

1 answer:

amm18123 years ago

6 0

Answer: The answer is that he cleaned one room

Step-by-step explanation:

Because he charged in total 77 dollars and he charged 77 dollars per room, so 77*1=77=c

You might be interested in

ABCD is a quadrilateral inscribed in a circle, as shown below:

german

Answer:

A. (x + 16) + (6x − 4) = 180

Step-by-step explanation:

Inscribed quadrilateral has opposite angles supplementary.

So

m∠A + m∠C = 180°

m∠B + m∠D = 180°.

Since

m∠A = x + 16,
m∠B = x,
m∠C = 6x - 4,
m∠D = 2x + 16

we can use either pair of angle measures to work out the value of x and then find the value of each angle.

We can verify the first option is the only correct one.

m∠A + m∠C = 180°
(x + 16) + (6x − 4) = 180

3 0

3 years ago

What is 6/7 Answer quickly please!!

nevsk [136]

Answer: 0.8

Step-by-step explanation:

6 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Find ten rational numbers between -2/5 and 1/2

Levart [38]

Answer:

-1/3, -1/4, -3/10, -1/8, -1/16, 1/3, 1/4, 3/10, 1/8, 2/5.

Step-by-step explanation:

-2/5 is -0.4 and 1/2 is 0.5

Ten rational numbers in between are, -0.33333 (-1/3), -0.25 (-1/4), -0.3 (-3/10), -0.125 (-1/8), -0.0625 (-1/16), 0.33333 (1/3), 0.25 (1/4), 0.3 (3/10), 0.125 (1/8), 0.4 (2/5)

5 0

3 years ago

Please help, will give brainliest. Thank you

xz_007 [3.2K]

Answer:

Thank you for your service. its appreciated

7 0

2 years ago

Read 2 more answers