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jek_recluse [69]
2 years ago
7

Wells Fargo has realized that they lose home mortgage business to other banks that can process the loan applications with less v

ariability in the time it takes to process each application. The bank recently studied this problem, and found that the processing time T is normally distributed with a mean of 13 days. They didnt measure the standard deviation, but they know that 50% of all applications were processed in between 10.5 and 15.5 days. After learning all this, they then fired half of their mortgage loan officers and replaced them with new recruits. They then sampled 25 applications, and found a sample mean of 13 days (same as the old) and a sample standard deviation of 2.5 days.
(a) Test whether their actions have significantly changed their processing time T.
(b) Based on the sample of 25 applications, give a 90% confidence interval for the parameter that
has changed.
Mathematics
1 answer:
-BARSIC- [3]2 years ago
4 0

Answer: B

Step-by-step explanation:

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If y=1/2x+5 then what is 2y+5x=-2
salantis [7]
(-2,4) 

2(1/2x+5)+5x=-2
x=-2

plug it back into and equation 

y=1/2*-2+5
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3 years ago
For what value of x is line a parallel to line b (9x+11)
Helga [31]

Answer:

15

Step-by-step explanation:

124° + 9x + 11 = 180 ➡ 9x = 135° ➡ x = 15

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3 years ago
An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he
timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, d_1 = 1\times610=610 miles.

The distance covered at 310 degrees, d_2 = 3\times610=1830 miles.

Total distance covered, d, is the magnitude of the sum of vectors \vec{d_1} and \vec{d_2} as shown in the figure.

The angle between the vectors \vec{d_1} and \vec{d_2}, \theta=310-270=40 degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}

\Rightarrow d=2330.51 miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0
3 years ago
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Roman55 [17]

Answer:

(f-g)(x)= x^2-4x-5

Step-by-step explanation:

We have the two functions:

f(x)=x^2-3x-10\text{ and } g(x)=x-5

And we want to find (f-g)(x).

(f-g)(x) is equivalent to f(x)-g(x).

Therefore:

\begin{aligned} (f-g)(x)&=f(x)-g(x)\\ &=(x^2-3x-10)-(x-5)\end{aligned}

Simplify:

\begin{aligned} &=x^2-3x-10-x+5 \\ &=(x^2)+(-3x-x)+(-10+5) \\ &=x^2-4x-5\end{aligned}

Therefore:

(f-g)(x)= x^2-4x-5

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