Ask question

Ask question

All categories

Arte-miy333 [17]

3 years ago

11

If j, k, and n are consecutive integers such that 0 < j < k < n and the units (ones) digits of the product jn is 9, wha

t is the units digits of k?

1 answer:

const2013 [10]3 years ago

7 0

All of those numbers have nothing but ones digits, that is, they're all single digits. j=4, k=5, and n=6.

You might be interested in

This test is literally the death of me but can anyone help?

Neporo4naja [7]

Answer:

answer is b

Step-by-step explanation:

i hope this helps you

7 0

3 years ago

Read 2 more answers

Which expression is equal to (6x−4)(3x−1)?

Natali5045456 [20]

Answer:

$(6x-4)(3x-1) = 18x^2 - 18x + 4$ is the required simplification.

Step-by-step explanation:

Here, the given expression is (6x−4)(3x−1).

By DISTRIBUTIVE PROPERTY of numbers:

A ( B + C ) = AB + AC

Simplifying the given expression, we get:

$(6x-4)(3x-1) = 6x(3x-1)-4(3x-1)\\= 6x(3x) -1(6x) -4(3x) +4\\=18x^2 - 6x - 12x + 4\\18x^2 - 18x + 4$

or, $(6x-4)(3x-1) = 18x^2 - 18x + 4$

Hence the given expression is simplified.

3 0

3 years ago

Suppose j varies jointly with g and v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.

vladimir2022 [97]

Answer:

$j=12$

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form $j = kgv$

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

$2 = k(4)(3)$

$2 = 12k$

$k=\frac{1}{6}$

The equation is equal to

$j=\frac{1}{6}gv$

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

$j=\frac{1}{6}(8)(9)$

$j=12$

3 0

3 years ago

25 points!! please answer

melomori [17]

ac is the answer

hope that helps

6 0

3 years ago

Read 2 more answers

Camilo estimates the weight of the dog . The veterinarian says that the dog weighs 84 pounds . The percent error in Camillo's es

blsea [12.9K]

Answer:

The estimated weight is in the range:

75.6 pounds $\leq$ Weight $\leq$ 92.4 pounds

Step-by-step explanation:

Since, the maximum error is 10%.

Therefore, the maximum and minimum vales will be 10% more and 10% less than 84 pounds, respectively.

<u>For Maximum Limit</u>:

$Weight_{max}$ = (1.1)(84 pounds)

$Weight_{max}$ = <u>92.4 pounds</u>

<u>For Minimum Limit</u>:

$Weight_{min}$ = (0.9)(84 pounds)

$Weight_{min}$ = <u>75.6 pounds</u>

Hence, the estimated weight is in the range:

75.6 pounds $\leq$ Weight $\leq$ 92.4 pounds

5 0

3 years ago