12 × 12 would equal to 144
Hope this helped! :D
Answer:
probability of an electric power outage shipboard is 0.075 or 7.5 %
Step-by-step explanation:
Given the data in the question;
Probability of engine malfunction = 25% = 0.25
Probability of generator malfunction = 10% = 0.1
Probability of generator being repaired = 50% = 0.5
probability of an electric power outage shipboard = ?
To get the probability of an electric power outage shipboard, we use the expression;
probability of an electric power outage = 2
× p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )
so we substitute in our given values;
probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )
probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75
probability of an electric power outage = 0.075 or 7.5 %
9514 1404 393
Answer:
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
Step-by-step explanation:
The applicable derivative formula is ...
d(u/v) = (v·du -u·dv)/v²
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f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²
f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²
f'(x) = (-6x² -14x -23)/(x² +5x +2)²
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Similarly, the second derivative is the derivative of f'(x).
f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴
f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³
f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³
9-2(-3)+6= 9+6+6 Your answer should be 21 if I read your question correctly
