Answer:
multiply the number in each can by the number of cans and add the extras
Step-by-step explanation:
You can add them all up. This is the total of the number in each can and the extras:
8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +8 +7
Or you can take advantage of the invention of multiplication to simplify repeated addition. Multiply the number in each can by the number of cans, then add the extras.
15×8 +7 = 127
<span>A=1000<span><span>(<span>1.023<span>112</span></span>)^</span><span>12<span>t 0.19%</span></span></span></span>
Remember, we can do anything to an equation as long as you do it to both sides
and distributive proeprty, reversed
ab+ac=a(b+c)
xm=x+z
minus x from both sides
xm-x=z
xm-1x
undistribute x
x(m-1)=z
divide both sides by (m-1)
You should know that:
(a+b)(a+b)(a+b)
=a(a+b)(a+b)+b(a+b)(a+b)
=a(a²+2ab+b²)+b(a²+2ab+b²)
=a³+2a²b+ab²+a²b+2ab²+b³
=a³+3a²b+3ab²+b³
-----------------
If a=5x and b=-4y
(5x+(-4y))³
=(5x-4y)³
=(5x)³+3(5x)²(-4y)+3(5x)(-4y)²+(-4y)³
=125x³+3(25x²)(-4y)+15x(16y²)-64y³
=125x³+75x²(-4y)+240xy²-64y³
=125x³-300x²y+240xy²-64y³
65 less than J in an algebraic expression would be " 65-j "
