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noname [10]
3 years ago
14

Nick walks 8 miles in 3 hours,and braylon walks 16 miles in 6 hours.what is the unit rate per hour

Mathematics
2 answers:
stich3 [128]3 years ago
6 0

Answer: 2.6

Step-by-step explanation:

wariber [46]3 years ago
3 0

Answer:

nick: 2.6/1

Braylon: 2.6/1

Step-by-step explanation:

they have the same unit rate per hour

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Find the length of CD shown in red below. Show all work.
PIT_PIT [208]

By definition of circumference, the length of the arc EF (radius: 6 in, central angle: 308°) shown in red is approximately equal to 32.254 inches.

<h3>How to calculate the length of an arc</h3>

The figure presents a circle, the arc of a circle (s), in inches, is equal to the product of the <em>central</em> angle (θ), in radians, and the radius (r), in inches. Please notice that a complete circle has a central angle of 360°.

If we know that θ = 52π/180 and r = 6 inches, then the length of the arc CD is:

s = [(360π/180) - (52π/180)] · (6 in)

s ≈ 32.254 in

By definition of circumference, the length of the arc EF (radius: 6 in, central angle: 308°) shown in red is approximately equal to 32.254 inches.

<h3>Remark</h3>

The statement has typing mistakes, correct form is shown below:

<em>Find the length of the arc EF shown in red below. Show all the work.</em>

To learn more on arcs: brainly.com/question/16765779

#SPJ1

4 0
2 years ago
PLEASE HELP IT'S DUE TODAY-
Marina86 [1]

bro.. i don't think someone is gonna answer all this for you, you should like figure this out on ur own..

8 0
3 years ago
Read 2 more answers
Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F.
erastova [34]

Answer:

E

Step-by-step explanation:

i guess the dotted lines outline a square

so get the area of the square which is 6×6=36

then don't focus on the shaded part but unshaded you'll see two right angled triangles

a = 1 \div2b \times h

you will get a total for both as 21

then get the area of the square 36-21=15

so the area becomes 15

3 0
3 years ago
A real estate agent has 1212 properties that she shows. She feels that there is a 50P% chance of selling any one property during
forsale [732]

Answer:

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

Step-by-step explanation:

For each property, there are only two possible outcomes. Either it is sold, or it is not. The probability of a property being sold is independent of any other property. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

12 properties

This means that n = 12

She feels that there is a 50% chance of selling any one property during a week.

This means that p = 0.5

Compute the probability of selling no more than 6 properties in one week.

This is:

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002

P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029

P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161

P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537

P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208

P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934

P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.2256

P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 + 0.1934 + 0.2256 = 0.6127

0.6127 = 61.27% probability of selling no more than 6 properties in one week.

6 0
2 years ago
Enter the unknown the value that makes this statement true: 30% of _____ is 60.
mina [271]
The answer of the unknown value is 90%

4 0
3 years ago
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