If 0 is a positive acute angle and 2 cos 0+3 = 4, find the number of degrees in 0.

Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta

Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0

3 years ago

Read 2 more answers

Help please!!!!!!!!!!!!!

KatRina [158]

Hello!

For this you can plug in the x values in the choices and see if you get the y value

y = $-4^{3} - (-4)$

-4^3 is -64

when you subtract a negative you are just adding

-64 + 4 = 60

Then you do the second one

$y = -3^{3} - (-3)$

-3^3 is -27

-27 + 3 is -24

Then the third one

$y = -2^{3} - (-2)$

-2^3 is -8

-8 + 2 is -6

Then the last one

$y = -1^{3} - (-1)$

-1^3 is -1

-1 + 1 = 0

Since we did not get -2 the answer is D

Hope this Helps!

7 0

3 years ago

HELP PLZZ I WILL REWARD IF ANSWERS RIGHT

pentagon [3]

I know you have 1 and 3 right but I'm sorry about not knowing the rest.

8 0

3 years ago

P is the incenter of △JKL. Find m∠JKP. & can you please explain

dangina [55]

Answer:

m∠MKP = 35°

Step-by-step explanation:

Incenter is the intersection of angle bisectors.

∠MJP = ∠OJP, ∠MKP = ∠NKP, ∠NLP = ∠OLP

First find the value of x:

7x - 6 = 5x + 4
7x - 5x = 4 + 6
2x = 10
x = 5

Find the angle MJP:

7*5 - 6 = 29°

We know sum of interior angles of a triangle is 180°. Using this find the missing angle measure:

2*m∠MJP + 2*m∠NJP + 2*m∠MKP = 180°
m∠MJP + m∠NJP + m∠MKP = 90°
29° + 26° + m∠MKP = 90°
m∠MKP = 90° - 55°
m∠MKP = 35°

7 0

3 years ago

Can y'all help me step by step with number 5

aev [14]

If the wall with 4 ft. of storage area can fit 6 sections of plant and the wall with 7 ft. Can fit 5, that means each section is 3 ft. because 7-4=3, so that extra section on the wall with 4 ft. You do this because there is one extra section on the wall with four. Knowing this, the wall with 7 ft. Would be the 7 ft. + 5 sections of 3 ft. So 7+(5x3) = 22. On the wall with 4 ft., do the same,
4+(6x3) =22. Since they are equal and the walls are supposed to be equal, we can confirm this is the right answer

6 0

3 years ago