Question

After 30 s, a runner is sprinting at 3 m/s. But, 10 s later, the runner is sprinting at 3.8 m/s. What is the runner's acceleration during this time?

Answer 1

We can consider that the runner did an acceleration of 0.8 m.s during the 10 seconds of difference.
We can deduce that the runner did an acceleration of 0.08 m.s every second during this time.

Answer 2

Answer:

0.08m/s²

Step-by-step explanation:

Acceleration is a rate, a rate of Velocity over Time. To measure it you have to know how fast someone,  or something in this case sprints at a given interval of time.

t1=30  V1=3m/s

t2=40  V2=3.8m/s

So, with all data collected. Let's calculate it:

$a=\frac{V_{2} -V_{1}}{T_{2}-T_{1}}=\frac{3.8-3}{40-30}\\ a=0.08m/s^{2}$

a=Δv/Δt

a= 0.08 m/s²

At 0.08 meters per square second the sprinter accelerates over a ten seconds period.