Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
It d over 3 u 2 text me if you need more help hope this helps u a little bit more.
He has $90 in total to spend
He spent (31/45) of this money on ticket
so money spent on ticket =(31/45) *90 =2790/45 =62
Now money left with him is 90-62 =28 $
Now it says that he spent (3/7) of this remaining money at concession stand
so money spent on concession stand =(3/7)*28 =84/7 =12
Now money left with him = 28-12 =16
So money left with him is $16 but hat costs for $18
So Mr. O'Connor didnt have enough moeny to buy the hat
