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klemol [59]
3 years ago
14

Is 15/35 less than equal then greater than 12/20

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
Its less than bc if you turn them into decimals, 15/53 would be 0.42 and 12/20 would be 0.60
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Solve 22.5 + x = -47.37<br><br> -24.87<br> 24.87<br> -49.62<br> -69.87
zheka24 [161]
The answer is -69.67

22.5 + x = -47.47
-22.5 -22.5
x = -69.87
4 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}​

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

8 0
2 years ago
Read 2 more answers
Which algebraic expression models the sum of 3 coins and c coins?
SpyIntel [72]
3+c i think that the answer.
7 0
3 years ago
if a staircase rises 52° from the ground and a vertical distance of 12 yards. How much horizontal distance does the staircase co
3241004551 [841]
The horizontal distance will be found using the formula:
tan θ= opposite/adjacent
given that θ=52°
opposite= 12 yards
adjacent=x
hence
tan 52=12/x
x=12/tan 52
x=9.3754
the height is 9.375 yards
3 0
2 years ago
Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con
andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers  = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers  = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers  = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

7 0
3 years ago
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