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garri49 [273]
3 years ago
7

Sanjay and Felipe are putting together a 500-piece puzzle. Sanjay could do the entire puzzle by himself in 6 hours, while it wou

ld take Felipe 8 hours to do the puzzle alone.
Use the table to write and solve an equation to determine the approximate amount of time it would take Sanjay and Felipe to do the puzzle if they were working together.

0.8 hours
1.7 hours
3.4 hours
7 hours
Mathematics
2 answers:
kicyunya [14]3 years ago
7 0
3.4 hours. The efficiency of a worker is the amount of work divided by time needed. The efficiency of Sanjay alone is 500/6, and the efficiency of Felipe alone is 500/8. When they work together, their combined efficiency is 500/6+500/8=3500/24. Therefore, they need 500/(3500/24)=24/7=3.4 hours.
Rina8888 [55]3 years ago
5 0
The answer would be

<span>3.4 hours
</span>
pls mark brainliest XD
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3 years ago
A population of protozoa develops with a constant relative growth rate of 0.469 per member per day. On day zero the population c
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If the growth rate is 0.469 per member per day and in the beginnning there are 5 members then the population size after eight days is 108.42.

Given growth of population of protozoa 0.469 per member per day and population in beginninng is 5 members.

We have to find the population afte eight days.

First of all we have to find the function or equation showing sum of population after t days.

Because it is given that the rate is 0.469 per member per day it means it is like compounding.

The equation which shows the sum after compounding is P(1+r)^{n}

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In this problem the equation will be 5(1+0.469)^{t} where t is number of days.

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