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Paladinen [302]
3 years ago
6

PLS HELP! (THE QUESTION IS A PICTURE CLICK ON THE QUESTION FIRST)

Mathematics
1 answer:
allsm [11]3 years ago
8 0
All triangles angles in the inside add up to 180, so 180-76-72=32
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Diego's mother is twice as old as he is she is also as old as the sum of the ages of diego and both of his younger twin brothers
OLEGan [10]
2d = d + 11 + 11 = d + 22
d = 22
Diego is 22 years old.
7 0
3 years ago
Which of the following is a solution to the inequality below?
kap26 [50]

Answer:

V>-8

Step-by-step explanation:

The given inequality is :

4-V>12

Subtracting 4 from both sides.

4-V-4 > 12-4

-V>8

or

V>-8

So, the value of V is more than -8.

7 0
3 years ago
How do I simplify −9(3−4w)−8w
laiz [17]
Multiply out the bracket so
-27 + 36w - 8w
Then collect the terms so
-27 + 28w

Answer = - 27 + 28w
3 0
3 years ago
Read 2 more answers
Question 1/8
just olya [345]

Answer:

discount = 290 × <u>1</u>

4

= 72.50

new price is

290.00

<u>72.50</u> -

217.50

5 0
3 years ago
A doctor is measuring the mean systolic blood pressure of female students at a large college. Systolic blood pressure is known t
Nana76 [90]

Answer:

The correct option is (b).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times\frac{SD}{\sqrt{n}}

The confidence interval for population mean can be computed using either the <em>z</em>-interval or <em>t</em>-interval.

The <em>t</em>-interval is used if the following conditions are satisfied:

  • The population standard deviation is not known
  • The sample size is large enough
  • The population from which the sample is selected is normally distributed.

For computing a (1 - <em>α</em>)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.<em>n</em> < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.

In this case the sample size is, <em>n</em> = 28 < 30.

Also it is provided that the systolic blood pressure is known to have a skewed distribution.

Since the sample is small and the population is not normally distributed, the  sampling distribution of sample mean will not be approximated by the normal distribution.

Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.

The correct option is (b).

5 0
3 years ago
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