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Bess [88]
3 years ago
5

Which of the above numbers is the value of expression equal to?

Mathematics
2 answers:
castortr0y [4]3 years ago
5 0
E is your right answer for this question have a nice day
babymother [125]3 years ago
4 0

Answer:

D.

4.33 \times  {10}^{6}

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Is 1.436 greater than 25/2
Alex Ar [27]

Answer:1.75 (1 3/4) is greater than 1 1/2. 0.25 is equivalent to 1/4. 0.2185 is not equal to 1/3, and 1.436 is less than 25/2 (12 1/2), hope it helped

Step-by-step explanation:

3 0
4 years ago
Estimate the product of 403 × 581 by rounding to the nearest hundred. A. 300,000 B. 240,000 C. 30,000 D. 24,000
irga5000 [103]

Answer:

It would be b.

Step-by-step explanation:

403x581=234143 rounded to 240,000

Hope it helped brainiest plz

8 0
3 years ago
X^2-8x+16=5 what are the solutions?
svp [43]
Hey!


The first step to solving this equation would be to subtract 5 from both sides of the equation.

<em>Original Equation :</em>
x^{2} - 8x + 16 = 5

<em>New Equation {Added Subtract 5 to Both Sides} :</em>
x^{2} - 8x + 16 - 5 = 5 - 5

Now we solve our new equation.

<em>Old Equation :</em>
x^{2} - 8x + 16 - 5 = 5 - 5

<em>Solution {Old Equation Solved} :</em>
x^{2} - 8x + 11 = 0

The next step would be to solve with the quadratic formula.

<em>Quadratic Equation ( 1 ) :</em>
x =  \frac{-(-8) +  \sqrt{(-8)^{2} -4 * 1 * 11 } }{2*1}

<em>Quadratic Equation ( 1 ) {Solved} :</em>
4 + \sqrt{5}

<em>Quadratic Equation ( 2 ) :</em>
x =  \frac{-(-8) -  \sqrt{(-8)^{2}-4 *1*11 } }{2*1}

<em>Quadratic Equation ( 2 ) {Solved} :</em>
4 - \sqrt{5}

<em>So, our final solutions for the equation x^{2} - 8x + 16 = 5 are...</em>

x = 4 + \sqrt{5}

<em>and </em>

x = 4 - \sqrt{5}

Hope this helps!


- Lindsey Frazier ♥
5 0
3 years ago
X² + 15x + 14 Solve this please
Yuri [45]

Answer:

(x+14)·(x+1)

Step-by-step explanation:

I just put the equation on Photomath....

6 0
3 years ago
Read 2 more answers
Using only the values given in the table for the function, f(x)=x^3-3x-2,
katen-ka-za [31]
It’s decreasing from -1 to 1.
6 0
3 years ago
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