Can someone please help me on this

Refer to parallelogram ABCD to answer to following questions.

alexdok [17]

Answer:

No: The diagonals are not congruent.

3 0

3 years ago

Amber went on a road trip over winter vacation. She recorded how far she had traveled in the table below in relation to the numb

svlad2 [7]

Answer:

B

Step-by-step explanation:

it shows every 4 hours, so:

560-336=224

224:4=56 per hour

6 0

2 years ago

Consider two forces of 17 and 42 pounds both acting in the horizontal direction on a single object. find the resultant force act

lys-0071 [83]

The forces have a magnitude of 59 pounds, and their direction angles are zero.

<h3>What is the magnitude of force?</h3>

The total amount of forces exerted on an object is referred to as the magnitude of force. The strength of the force increases when all the forces are pulling in the same direction. The force's strength reduces when forces are exerted on an item from different angles.
When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out. When two forces operating on a body in opposite directions along the same line of action are equal in magnitude, they cancel one another out.
According to this formula, the amount of net force acting on an item is equal to the mass times the acceleration of the object.
Magnitude is a term that refers to size or importance. The depth of the Grand Canyon serves as an illustration of magnitude. The scope of the hunger crisis in the world serves as an illustration of magnitude. A measurement of the energy released by an earthquake, as shown on the Richter scale (geology).

Two forces of 17 and 42 pounds act horizontally on an object.

i.e

F1 = 17 pounds

F2 = 42 pounds

As the magnitude of the force represents the sum of all the forces

The direction is the same

Magnitude : 17 + 42 = 59 pounds

The Direction angles : 0

As they have the same direction so angle will be 0.

The forces have a magnitude of 59 pounds, and their direction angles are zero.

To learn more about the Magnitude of forces and Direction angles of forces, refer to:

brainly.com/question/14584426

#SPJ4

7 0

2 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago