Quadrilateral. If you add the angles up on any quadrilateral, it equals 360 (it should always add to 360 for a quadrilateral)
Answer:
2
Step-by-step explanation:
|x| means absolute value
|x| means if x is positive or negative, its still positive
-5|x|+4=14
-5|x|=10
|x|= -2
answer is 2
Let that be
![\\ \rm\Rightarrow y=\dfrac{a(f(x))}{g(x)}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRightarrow%20y%3D%5Cdfrac%7Ba%28f%28x%29%29%7D%7Bg%28x%29%7D)
Two vertical asymptotes at -1 and 0
![\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x(x+1)}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRightarrow%20y%3D%5Cdfrac%7Ba%28f%28x%29%7D%7Bx%28x%2B1%29%7D)
If we simply
![\\ \rm\Rightarrow y=\dfrac{a(f(x)}{x^2+1}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRightarrow%20y%3D%5Cdfrac%7Ba%28f%28x%29%7D%7Bx%5E2%2B1%7D)
- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is
![\\ \rm\Rightarrow y=\dfrac{3x^2+9x}{x(x+1)}](https://tex.z-dn.net/?f=%5C%5C%20%5Crm%5CRightarrow%20y%3D%5Cdfrac%7B3x%5E2%2B9x%7D%7Bx%28x%2B1%29%7D)
Graph attached
Answer:
hello : k = - 9
Step-by-step explanation:
h(x) =x²+3 and g(x) = x² - 6.....(*)
g(x) = x² +3 + k.....(**)
by (*) and (**) : 3+k = -6
3+k - 3 = - 6 - 3
k = - 9
Answer:
just add the equation and solve it then the value of X could be found then put the value of X and the value of y can be found. Just like in the below
Step-by-step explanation:
X+y=3 ------------ equation 1
4x-y=7 ------------ equation 2
adding equation 1 and 2
X+y=3
+ 4x-y=7
-----------------
5x = 10
X = 10/5
X = 2
putting the value of X in equation 1
or, 2+y=3
or, y = 3-2
Thus, y = 1