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Wewaii [24]
3 years ago
11

Solve for x. 4x - 14 x + 85 x = [?]

Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

x = 33

Step-by-step explanation:

4x - 14  = x + 85

3x = 99

x = 99/3

x = 33

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The diameter of the pizza is 16 inches therefore the area of the pizza is what rounded to the nearest whole number
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Answer:

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Read 2 more answers
Exam grades across all sections of introductory statistics at a large university are approximately normally distributed with a m
adelina 88 [10]

Answer:

a) 4.18% of students scored above a 91

b) 20.61% of students scored below a 63

c) A grade of 52.75 is the cutoff for being required to attend these sessions

d) The cutoff to get an A is a grade of 86.08.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72, \sigma = 11

(a) What percent of students scored above a 91?

This is 1 subtracted by the pvalue of Z when X = 91. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{91 - 72}{11}

Z = 1.73

Z = 1.73 has a pvalue of 0.95682

1 - 0.9582 = 0.0482

4.18% of students scored above a 91

(b) What percent of students scored below a 63?

This is the pvalue of Z when X = 63. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63 - 72}{11}

Z = -0.82

Z = -0.82 has a pvalue of 0.2061.

20.61% of students scored below a 63

(c) If the lowest 4% of students will be required to attend peer tutoring sessions, what grade is the cutoff for being required to attend these sessions?

This is the value of X when Z has a pvalue of 0.04. So it is X when Z = -1.75.

Z = \frac{X - \mu}{\sigma}

-1.75 = \frac{X - 72}{11}

X - 72 = -1.75*11

X = 52.75

A grade of 52.75 is the cutoff for being required to attend these sessions

(d) If the highest 10% of students will be given a grade of A, what is the cutoff to get an A?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 72}{11}

X - 72 = 1.28*11

X = 86.08

The cutoff to get an A is a grade of 86.08.

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