Answer:B)The values of both x and y will be real numbers greater than or equal to 0.
Step-by-step explanation:
Answer:
2i, if you don't understand any of the steps let me know, I'd be happy to explain.
Step-by-step explanation:
so in order -4 = -1 * 4 so then 
then just solve each
The percent equivalent to 1 / 4 = 25 %.
The percent equivalent to 3 / 4 = 75 %.
25 % x 3 = 75 % ( correct )
The 21st term of the given arithmetic sequence is 83. The nth term of an arithmetic sequence is applied to find the required value where n = 21.
<h3>What is the nth term of an arithmetic series?</h3>
The nth term of an arithmetic sequence is calculated by the formula
aₙ = a + (n - 1) · d
Here the first term is 'a' and the common difference is 'd'.
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
3, 7, 11, 15, 19, ....
So, the first term in the sequence is a = 3 and the common difference between the terms of the given sequence is d = 7 - 3 = 4.
Thus, the required 21st term in the sequence is
a₂₁ = 3 + (21 - 1) × 4
⇒ a₂₁ = 3 + 20 × 4
⇒ a₂₁ = 3 + 80
∴ a₂₁ = 83
So, the 21st term in the given arithmetic sequence is 83.
Learn more about the arithmetic sequence here:
brainly.com/question/6561461
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Answer:
// C++ Program to arithmetic operationf on 2 Numbers using Recursion
// Comments are used for explanatory purpose
#include <bits/stdc++.h>
using namespace std;
// add10 recursive function to perform arithmetic operations
int add10(int m, int n)
{
return (m + product(n, 10)); //Result of m + n * 10
return 0;
}
// Main Methods Starts here
int main()
{
int m, n; // 2 Variables m and n declared as integer
cin>>m; // accept input for m
cin>>n; // accept input for n
cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n
return 0;
}
