10 + (-3 3/8) = i need the answer

Mathematics

1 answer:

ratelena [41]3 years ago

3 0

Answer:6 . 625 or 6 5/8

Step-by-step explanation

10 + (-3 3/8) (adding a negative is like subtracting a positive)

10 - 3 3/8

6 5/8

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Use the grouping method to factor this polynomial x ^ 3 + 2x ^ 2 + 7x + 14

elena55 [62]

Answer:

B. ( $x^{2}$ +7)(x+2)

Step-by-step explanation:

The greates common factor between 7 and 14 is 7 so you know that one of the terms is going to be 7....but what times 7 equals 14...2

So we know that in one set of parentheses its going to be (something +2) and in another (something +7)

Well if we know that one is going to be 2, how do we go from 2 to 2 $x^{2}$ .....2 times $x^{2}$ equals $2x^{2}$

So now we know that one set of parentheses is going to be (something + 2) times ( $x^{2}$ +7)

So lastly, we have to find out how to get $x^{3}$ but since we already have a $x^{2}$ in the second set of parentheses all we have to do is put a x in the first set because x times $x^{2} = x^{3}$

Hope this helps!

6 0

3 years ago

The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with

kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

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