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anzhelika [568]
3 years ago
15

If the function h is defined by h(x)=

lign="absmiddle" class="latex-formula">-3x+5,then h(2x+1)=
Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

Given:

The function is:

h(x)=x^2-3x+5

To find:

The value of h(2x+1).

Solution:

We have,

h(x)=x^2-3x+5

Putting x=2x+1, we get

h(2x+1)=(2x+1)^2-3(2x+1)+5

h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5

h(2x+1)=4x^2+4x+1-6x-3+5

On combining like terms, we get

h(2x+1)=4x^2+(4x-6x)+(1-3+5)

h(2x+1)=4x^2-2x+3

Therefore, the required function is h(2x+1)=4x^2-2x+3.

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Well
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A scuba diver is diving at a constant rate when her
Helen [10]

Answer:

-0.25 ; 120 seconds 72 seconds

Step-by-step explanation:

Dive rate is constant :

Change in elevation after 8 seconds :

18 feets to 20 feets below

Rate of change = distance / time

(18 - 20) feets / 8 seconds

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4 0
2 years ago
How to didvie $50 in the ratio of 2:3
Rama09 [41]
50 divided 2/3

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5 0
3 years ago
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In the figure, line m is parallel to line n. The measure of angle 2 is 40 degrees and the measure of angle 3 is 68 degrees. What
sveticcg [70]

Answer:

∠1 - 40°

Step-by-step explanation:

∠1 - 40°

b/c it's a right triangle and we have two angles given, 50° and 90°. Add them and subtract by 180° and get 40°.

∠2 - 140°

b/c an exterior (outside) angle is equal to the two most isolated / farthest angles added. The two most is angles are 105° and 35°, add them and get 140°.

∠3 - 40°

b/c ∠'s 1 and 3 are vertical angles meaning they're equal so since ∠1 is 40°, so is ∠3.

∠4 -

b/c ∠' s 2 and 4 are vertical angles meaning they're equal so since ∠2 is 140°, so is ∠4.

∠5 - 35°

b/c we have two angles, 105° and 40°. Add them and subtract by 180° and get 35°.

hope that helps lol >:)

4 0
2 years ago
Help me please asap :(
GREYUIT [131]
This is a fairly tedious problem. The only way to solve that I see is to simply list out all the possible cases and go through each one by one. You'll use the triangle inequality theorem to see if the triangles can be formed. The theorem says that a+b > c must be true for all sets of pairs. In other words, take any two sides and add them up. The sum must be greater than the third side. 

Going through all the combos possible (that I could find), this is what I got
Blue9,Green7,Orange4
Blue9,Green7,Purple12
Blue9,Green7,Red3
Blue9,Green7,Yellow5
Blue9,Orange4,Purple12
Blue9,Purple12,Yellow5
Green7,Orange4,Yellow5
Green7,Red3,Yellow5
Orange4,Red3,Yellow5

In all, I count 9 cases. So the answer to problem 1 is 9.

-----------------------------------------------------------

For problem 2, the best way may be to pick two segments at a time instead of one. However, I have a feeling that will take just as long as the first method. I haven't tried it out. Even though going through the rods one at a time takes a while, it's probably the best option so you don't overlook any cases. 


6 0
3 years ago
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