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3 years ago

Please help will give branliest

Mathematics

2 answers:

chubhunter [2.5K]3 years ago

5 0

Answer:

-2x + 8y -3

Step-by-step explanation:

-2x = -2x

2y + 6y = 8y

-3 = -3

NikAS [45]3 years ago

3 0

-2x+8y-3

Hope this helps! :)

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Find the surface area of the pyramid. The side lengths of the base are equal. Square pyramid with base edge of 12 centimeters, a

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Answer:

the surface area of the square pyramid is 576.66 cm^2

Step-by-step explanation:

The computation of the surface area of square pyramid is given below:

A = a^2 + 2a × √a^2 ÷ √4 + √h^2

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3 years ago

The circle passes through the point (−2, 3) with a center of (-4,6). What is its radius?

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(x - h)² + (y - k)² = r²

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2 years ago

You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample

Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma=160)$

And the distribution for $\bar X$ is:

$\bar X \sim N(\mu, \frac{160}{\sqrt{n}})$

We know that the margin of error for a confidence interval is given by:

$Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The next step would be find the value of $\z_{\alpha/2}$ , $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$

Using the normal standard table, excel or a calculator we see that:

$z_{\alpha/2}=\pm 1.96$

If we solve for n from formula (1) we got:

$\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}$

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

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$n=(\frac{1.96(160)}{78.4})^2 =16$

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

$n=(\frac{z_{\alpha/2} \sigma}{Me})^2$

And now we can replace the new value of Me and see what we got, like this:

$n=(\frac{1.96*160}{60})^2 =27.32$

And if we round up the answer we see that the value of n to ensure the margin of error required $Me=\pm 60$ $ is n=28.

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