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2 years ago

10

Solve the perimeter formula of a rectangle for w and use the resulting formula to find the width of a rectangle with a length of

12 cm and a perimeter of 26 cm.

1 answer:

dusya [7]2 years ago

5 0

Answer:

Step-by-step explanation:w=1cm

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that there exists a pair of consecutive integers such that one of these integers is a perfect square and the other is a perfect

Brrunno [24]

$0=0^2$
$1=1^3$

Or are you looking for nontrivial pairs?

6 0

2 years ago

SOMEONE PLEASE HELP!!

Harrizon [31]

Answer
i believe the answer would be b

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3 years ago

Read 2 more answers

Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -36 and 2304, respectively.

Lorico [155]

Answer:

I think it's B.)

Step-by-step explanation:

3 0

2 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

2 years ago

Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a

Softa [21]

Answer:

a). $4.86\times 10^{-15}$ m

b). $4.21\times 10^{-2}$ m³

c). $7.00\times 10^{3}$ N²

Step-by-step explanation:

In this question we have to convert each option into SI units.

a). $4.86(10^{-6})^{2}$ mm

= $4.86\times (10^{-12})\times (10^{-3} )$ m

= $4.86\times 10^{-15}$ m

b). (348 mm)³

= $(348)^{3}\times (10^{-3})^{3}$ m³

= $42144192\times 10^{-9}$ m³

= $4.21\times 10^{-2}$ m³

c). $(83700)^{2}\times (10^{-3})^{2}$ N²

= $700569\times 10^{4}\times 10^{-6}$ N²

= $7.00\times 10^{9}\times 10^{-6}N^{2}$

= $7.00\times 10^{3}$ N²

7 0

2 years ago