Answer:
Mike is not right
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z----> the scale factor
x----> surface area of the enlarged rectangular prism
y-----> surface area of the original rectangular prism

so
In this problem we have

substitute



so
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
therefore
Mike is not right
<em>Verify with an example</em>
we have a rectangular prism



The surface area of the prism is equal to

substitute the values

If he doubles each dimension of any rectangular prism
then
the new dimensions will be



The new surface area will be


therefore
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
Answer:
the queen, the workers, and the drones. :)
Answer:
Step-by-step explanation:
Adjacent angles of parallelogram are supplementary.
∠A + ∠D = 180
Divide both sides by 2
∠A +
∠D = 90
∠PAD + ∠ADP = 90 --------------------(I)
IN ΔPAD,
∠PAD + ∠ADP + ∠APD = 180 {angle sum property of triangle}
90 + ∠APD = 180 {from (I)}
∠APD = 180 - 90
∠APD = 90
∠SPQ = ∠APD {vertically opposite angles}
∠SPQ = 90°
Similarly, we can prove ∠PQR = 90° ; ∠QRS = 90° and ∠RSP = 90°
In a quadrilateral if each angle is 90°, then it is a rectangle.
PQRS is a rectangle.
199 subjecting 100 equals 99. She has 99 left
(3a+2)(4a+5) ......expand
12a^2+15a+8a+10 .......group like terms 15a + 8a
12a^2+23a+10 ....this s the answer!