If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
#3
A(x) = 1000(1+.17)x
because the 17 percent would have to be changed to a decimal form
D)4 is the answer jcidifodofif
If he grew 12 flowers with 3 seed packets then there should be 4 seeds in one packet > 3 x 4 = 12
Devin needs 5 seed packets to have a total of 20 flowers in his garden
> 4 x 5 = 20
