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3 years ago

What is the standard form of this function?

Mathematics

1 answer:

Solnce55 [7]3 years ago

8 0

Answer:

D. Rx) = x2 - 4x + 10

Step-by-step explanation:

R(x)=(x-2)^2+6

=(x-2)(x-2)+6

=x^2-2x-2x+4+6

=x^2-4x+10

R(x) = x^2 - 4x + 10

Option D is the answer

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Assume that the random variable X is normally distributed, with mean mu equals 100 and standard deviation sigma equals 20. Comp

TEA [102]

Answer: 0.2119

Step-by-step explanation:

We assume that the random variable X is normally distributed.

Given : Population mean : $\mu=100$

Standard deviation : $\sigma=20$

Z-score : $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to 116

$z=\dfrac{116-100}{20}=0.8$

By using the standard normal distribution table for z , we have

$P(x>116)=P(z>0.8)=1-P(z\leq0.8)$

$=1-0.7881446\approx0.2119$

Hence, the required probability = 0.2119

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3 years ago

What are the domain and range of f(x) = |x + 6|?

san4es73 [151]

9514 1404 393

Answer:

domain: all real numbers
range: y ≥ 0

Step-by-step explanation:

The function is defined for all values of x, so its domain is all real numbers.

The function can produce values of f(x) that are 0 or greater, so its range is ...

y ≥ 0

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2 years ago

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cricket20 [7]

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3 years ago

Read 2 more answers

If a sample of 362 customers is taken from a population of 5530 customers,

inysia [295]

Using concepts of sample and population, it is found that the sample variance is representative of 362 and 5530 customers ages, option D.

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In sampling, the information is taken from a sample, and is used to estimate it for the whole population.

In this problem, we have a sample of 362 and a population of 5530 customers.
The sample variance $s^2$ is calculated from the sample, and used as an estimate for the population variance. Thus, it can be said that it represents both 362 and 5530 customers, and the correct option is D.

A similar problem is given at brainly.com/question/4086221

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1 year ago

Which is the graph of the function f(x) = x^3 + 6x^2 + 11x + 6?

Ganezh [65]

Here you go.. hope this helps

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3 years ago