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2 years ago

What year is 7 years after 2003

Mathematics

2 answers:

mezya [45]2 years ago

6 0

Answer:

2010

Step-by-step explanation:

asambeis [7]2 years ago

4 0

Answer: 2010

Step-by-step explanation:

2003+7=2010

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing.

Vesnalui [34]

Answer:

Step-by-step explanation:

Just like the last time that you asked this question, when you multiply the x^2 part of the parabolic function by a certain coefficient, the graph is stretched by that amount. When you add a certain amount, the graph is shifted up that much. Hope this helps!

5 0

3 years ago

A line with a slope of 0 passes through the point (-5, 6) . what is its equationin slope -intercept form?

IrinaVladis [17]

$y = 6$
the equation is the horizontal line which parts through (-5,6), since it has no slope.

3 0

3 years ago

Radioactive uranium-235 has a half-life of about 700 million years. Suppose you find a rock and chemical analysis tells you th

Natalka [10]

Answer:

A. 2.8 billion years old

Step-by-step explanation:

1/16 = (1/2)^4, so 4 half-lives have elapsed.

4 · 0.700 billion years = 2.8 billion years

The rock is 2.8 billion years old.

5 0

3 years ago

Read 2 more answers

Find the minimum and maximum of f(x, y, z) = y + 4z subject to two constraints, 2x + z = 4 and x2 + y2 = 1. g

yuradex [85]

$L(x,y,z,\lambda_1,\lambda_2)=y+4z+\lambda_1(2x+z-4)+\lambda_2(x^2+y^2-1)$

$L_x=2\lambda_1+2\lambda_2 x=0\implies\lambda_1+\lambda_2x=0$
$L_y=1+2\lambda_2y=0$
$L_z=4+\lambda_1=0\implies\lambda_1=-4$
$L_{\lambda_1}=2x+z-4=0$
$L_{\lambda_2}=x^2+y^2-1=0$

$\lambda_1=-4\implies \lambda_2x=4\implies\lambda_2=\dfrac4x$
$1+2\lambda_2y=0\implies\lambda_2y=-\dfrac12\implies8y=-x$

$x^2+y^2=1\implies (-8y)^2+y^2=65y^2=1\implies y=\pm\dfrac1{\sqrt{65}}$
$y=\pm\dfrac1{\sqrt{65}}\implies x=\mp\dfrac8{\sqrt{65}}$
$2x+z=4\implies z=4\pm\dfrac{16}{\sqrt{65}}$

We have two critical points to consider: $\left(-\dfrac8{\sqrt{65}},\dfrac1{\sqrt{65}},4+\dfrac{16}{\sqrt{65}}\right)$ and $\left(\dfrac8{\sqrt{65}},-\dfrac1{\sqrt{65}},4-\dfrac{16}{\sqrt{65}}\right)$ .

At these points, we respectively have a maximum of $16+\sqrt{65}$ and a minimum of $16-\sqrt{65}$ .

6 0

3 years ago

Which of the following illustrates the truth value of the given conditional statement?

rosijanka [135]

Answer:

OPTION C

Step-by-step explanation:

p: 10 > 7 is a true statement.

So, the truth value is T.

q: 10 > 4 is again a true statement.

So, the truth value of this statement again would be T.

So, p and q are true statements.

T & T -----> T.

So, OPTION C is the answer.

4 0

2 years ago