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Oduvanchick [21]
3 years ago
7

Pls help it's due soon pls dont waste my points i have so less :(

Mathematics
1 answer:
erica [24]3 years ago
7 0

Answer:

Cheetah ran for 3 hours.

Antelope ran for 5 hours.

Lion ran for 6 hours.

Elephant ran for 10 hours.

You might be interested in
Factor completely 56a2b3 − 35ab.
VMariaS [17]

I would start off by taking away 1a. That would make the problem be 56ab3-35b.I only took away 1 because each have at least 1a and is okay to do.


Next I would deal with the variable b. I would cross of 1 b. That's because both sides have at least 1b.  Now, it's shortened to be 56ab2-35.


Since you cannot take away anymore variables, you have to deal with 56 and 35. I start small with dividing each by 2. I am trying to see what the greatest number could be while making the numbers still be whole. That turns 56 into 28 when it's cut in half. The 35 now turns into 17.5.


I would assume your teacher would want the numbers to be whole. seeing as though when 35 is cut in half and makes a decimal number, I would leave them. What I mean by that is to leave the numbers as 56 and 35.


So, that means the answer is 56ab2-35.


I hope this helps!! (And makes sense)

5 0
3 years ago
What is the nearest ten and hundred 622
Zepler [3.9K]
622

rounded to nearest tens = 620
rounded to nearest hundreds = 600
8 0
3 years ago
Read 2 more answers
Give any two rational number between _1/2 and _1/5.
krok68 [10]

what numbers are betwwen 2 and 5? ......<em> 3 and 4</em>

\frac{1}{3} and \frac{1}{4}

You can check this by converting them into decimals.

\frac{1}{2} = .50

\frac{1}{3} = .33

\frac{1}{4} = .25

\frac{1}{5} = .20

Answer: \frac{1}{3} and \frac{1}{4}

4 0
3 years ago
Read 2 more answers
5 (cos25 + i sin25) / 2 (cos80 + i sin80)
steposvetlana [31]
I think the first step is to distribute the answers. 
3 0
4 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
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