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Citrus2011 [14]
3 years ago
15

Which expression is equivalent to 8 - (6r+2) ? -6r + 6 2r + 2 6r + 10 -6r + 10

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

-6r+6

Step-by-step explanation:

8-(6r+2)

8-6r-2

-6r+6

Phantasy [73]3 years ago
7 0

Answer:

-6r +6.

Step-by-step explanation:

Given : 8 - (6r+2) .

To find : Which expression is equivalent .

Solution : We have given 8 - (6r+2) .

Remove the parenthesis

8 - 6r -2.

Combine like terms

-6r +8 -2.

-6r +6.

Therefore, -6r +6.

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A student estimated a mass to be 250 grams but upon carefully measuring it, he found the actual mass to be 240 grams. What is th
disa [49]
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The 5 in 6.052 has 1/10 the value of the 5 in ? Please explain
zepelin [54]
The tenths place, starting from the right, it gets higher going to the left. so the tenths place is only ten times greater than it.
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3 years ago
What is the area of a section of pavement that is 10 ft wide and 70 yd​ long? Give your answer in square feet. I think I have th
Elenna [48]

Answer:

  2100 ft²

Step-by-step explanation:

1 yard is 3 ft, so 70 yards is (70 yd)×(3 ft/yd) = 210 feet.

The area of the pavement is the product of its length and width:

  area = (210 ft)(10 ft) = 2100 ft²

_____

If you keep the units with the numbers as I have done here, you find that the product of (10 ft) and (70 yd) does not have the units of ft². Rather, the units are ft·yd, which is <em>not what the problem is asking for</em>.

6 0
3 years ago
Which ordered pair is a solution of the equation?<br> Y-4=7(x-6)
deff fn [24]

Answer:

(6,4)

Step-by-step explanation:

The equation is in 'point-slope' form.

y-y_1=m(x-x_1)\\\rule{150}{0.5}\\(x_1,y_1) \rightarrow \text{a point that's given}\\\\m \rightarrow \text{slope}

This means we can identify the point that was used in the equation.

y-\boxed{y_1} =m(x-\boxed{x_1}) | y-\boxed{4}=7(x-\boxed{6})\\\rule{210}{0.5}\\y_1 = 4\\\\x_1 =6\\\rule{210}{0.5}\\(x_1,y_1) \rightarrow \boxed{(6,4)}

(6,4) would be a solution to the equation given.

Hope this helps.

4 0
2 years ago
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