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3 years ago

Find the area, in square meters, of an equilateral triangle with a perimeter of 36 m.

Mathematics

1 answer:

Citrus2011 [14]3 years ago

6 0

I hope it helps you!!!

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125+[-125]=? PLEASE HELP?!

elena55 [62]

The answer to this question is 0.

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3 years ago

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Solve the simultaneous equations:<br><br> 3a-2b=14 <br> 12a+9b=39

kirill [66]

Use elimination
Multiply first equation by 4
12a - 8b = 56
12a + 9b = 39
Subtract both
-17b = 17
b = -1
Plug in -1 for b
3a - 2(-1) = 14
3a = 12, a = 4
Final answer: a = 4, b = -1

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3 years ago

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Anna71 [15]

Answer: No answer

Step-by-step explanation:

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2 years ago

The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,

juin [17]

Answer:

The width is: $w(x)=4x^2$

The length is $l(x)=2x^2+3x+5$

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

$a(x)=8x^5+12x^3+20x^2$

The width of the rectangle is the greatest common factor of $8x^5$ , $12x^3$ and $20x^2$

That is the width is: $w(x)=4x^2$

We now divide the area by the width to obtain the length of the rectangle:

$l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}$

This simplifies to:

$l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}$

$l(x)=2x^2+3x+5$

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3 years ago

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Which numbers is a solution to x>10

IceJOKER [234]

14 > 10

all the numbers that bigger than 10 can replace x

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3 years ago