5.a) Steve - 60=5×12
= <u>5×3×2×2</u>
5.b) Ian - 60=6×10
= <u>3×2×5×2.</u>
<u>Discussion</u> - The prime factors reduce to the same numbers in both Steve's and Ian's case.
5.c) Case 1 of 48 = 6×8
= <u>3×2×2×2×2.</u>
Case 2 of 48 = 12×4
= <u>2×2×3×2×2.</u>
Answer:
3xz5+2x+4y−2z
Step-by-step explanation:
2x−5y+3z5x+9y−2z
=2x+−5y+3xz5+9y+−2z
Combine Like Terms:
=2x+−5y+3xz5+9y+−2z
=(3xz5)+(2x)+(−5y+9y)+(−2z)
=3xz5+2x+4y+−2z
So I have the same problem with you
SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
In the question, we are looking at the absolute value function which says that:
Based on this, we have that:
